purlJam

<planning>
1. **Design Strategy**:
   - Single size: 48" chest circumference with 10cm (~4") positive ease → target bust = 48" + 4" = 52" finished chest
   - Wait — re-reading: "48 inch size only with 10cm positive ease" — this means the wearer's chest is 48" and the finished garment has 10cm (~4") positive ease, so finished chest = 48" + ~4" = 52" (132cm)
   - Actually re-reading again: the sizes listed are XL (46-48") so the wearer fits XL. With 10cm ease: finished = ~122cm chest + 10cm = 132cm finished
   - Let me use: wearer chest = 122cm (48"), finished = 132cm (52")
   - Yarn: 5ply (sport weight in AU/UK terminology — "5ply" is Australian term roughly equivalent to sport/fine DK, approx 22-24 sts per 10cm)
   - Wait — "5ply" in Australian/UK context = sport weight, approximately 22 sts / 10cm on 3.75mm needles
   - Celtic cable motif on: sleeves, body, neck cuff
   - Body ONLY in half fisherman's rib (this is a key design note — the stockinette/plain areas of the body are in half fisherman's rib, but the cables will be worked in regular knit/purl as cables don't work in fisherman's rib)
   - V-neck raglan, top-down, seamless
   - This is advanced difficulty

2. **Construction Plan**:
   - Top-down V-neck raglan
   - V-neck: Begin with very few stitches at the base of the V, work short rows or provisional cast-on up to the shoulders, OR work from the deepest point of the V upward with increases for V-shaping AND raglan increases simultaneously
   - Better approach for V-neck top-down raglan: Start at back neck, work back neck first with short rows, then join front V, OR start at the tip of the V and work upward
   - Standard method: Cast on a small number of stitches for the back neck, work the raglan yoke, shaping the V-front by starting with fewer front stitches and increasing along the front edges as well as at raglan lines
   - Actually the cleanest V-neck top-down raglan: 
     * Start with provisional cast-on at back neck
     * Work the raglan yoke flat first, building the V by adding front stitches, then join in the round once the V reaches desired depth
     * OR: Use the "Elizabeth Zimmermann" approach — start at back, work back and forth with V-neck shaping
   - I'll use the standard advanced method: Begin at the back neck with a provisional cast-on, work back and forth adding front stitches at each end to create the V, all while doing raglan increases, then join in the round when the V is complete
   - Celtic cable design: I need to design a specific Celtic cable motif. Classic Celtic cables often feature interlaced patterns. I'll design a 12-stitch Celtic cable (or 16-stitch) that can be used on sleeves, body panels, and neck cuff.
   - Half fisherman's rib for body background (non-cable areas): This is k1, slip 1 purlwise with yarn in front, alternating. It creates a ribbed effect. Since we're working in the round, half fisherman's rib in the round = k1, sl1wyif alternating
   - Neck cuff: V-neck with cable, worked as a neckband after the yoke

3. **Quality Assurance**:
   - Celtic cables in half fisherman's rib background: The cable panels will be worked in standard knit stitches (not fisherman's rib) with reverse stockinette or seed stitch borders to make them pop. The background between cables is half fisherman's rib.
   - The sleeves are NOT in half fisherman's rib (user specified body only) — sleeves have the cable motif against a stockinette or reverse stockinette background
   - V-neck construction: Need to carefully work out the stitch count for the provisional start
   - Raglan math: Need to ensure the increases work out to the correct chest circumference
   - Cable chart: Need a proper Celtic cable design

4. **Final Calculations**:
   - Yarn: 5ply / sport weight
   - Tension: 24 sts × 32 rows = 10cm × 10cm in stockinette on 3.75mm needles
   - For half fisherman's rib: due to the nature of the stitch, the stitch count will be the same but the fabric is wider/denser — tension in half fisherman's rib will be different. Approximately 20 sts = 10cm in half fisherman's rib (fisherman's rib tends to compress laterally)
   - I need to unify this — the body is in half fisherman's rib with cable panels. The cable panels will be a fixed width. The background will be half fisherman's rib.
   - Let me establish tensions:
     * Stockinette tension: 24 sts / 10cm = 2.4 sts/cm
     * Half fisherman's rib tension: approximately 20 sts / 10cm = 2.0 sts/cm (rib pulls in but fisherman's rib has less pull-in than regular rib — let me recalculate: half fisherman's rib is about 10-15% narrower than stockinette, so ~21-22 sts/10cm)
     * I'll use 22 sts/10cm for half fisherman's rib
   
   - Target finished chest = 132cm
   - Total body stitches needed: 132cm × 2.2 sts/cm = 290.4 → round to usable number with cable repeats
   
   - Cable panel: Let me design a Celtic cable that is 16 stitches wide (a classic Celtic interlace). I'll use 2 cable panels on each front, 2 on each back panel, and on sleeves.
   
   Actually, let me reconsider the design more carefully:
   
   **Celtic Cable Design**: I'll design a 16-stitch panel Celtic cable with a 24-row repeat. Classic Celtic cables use interlocking C4F and C4B crossings to create an interlaced look.
   
   A classic Celtic panel (16 sts):
   - Features two interlocked 4-stitch cables
   - 24-row repeat
   
   Let me design this:
   Row 1 (RS): p2, k4, p4, k4, p2
   Row 2 (WS): k2, p4, k4, p4, k2
   Row 3: p2, C4F, p4, C4B, p2
   Row 4: k2, p4, k4, p4, k2
   Row 5: p2, k4, p4, k4, p2
   Row 6: k2, p4, k4, p4, k2
   Row 7: p2, k2, C4B, C4F, k2, p2... 
   
   Hmm, let me think about a proper Celtic cable panel. A well-known Celtic cable is:

   **16-stitch Celtic Plait/Interlace Cable**:
   This uses a traveling stitches/bobble approach. Let me design a cleaner version:

   For a 12-stitch Celtic diamond cable panel:
   Multiple of 12 + some border stitches
   
   Actually, let me design a clean Celtic cable that works. A classic Celtic interlace (12 sts):
   
   Row 1: k2, p2, k4, p2, k2
   Row 2 and all WS: work stitches as they appear (k the k, p the p)
   Row 3: C4B (but that's only 4 sts)...
   
   Let me use a well-established Celtic cable pattern:
   
   **Celtic Cable (panel of 16 sts)**:
   This is a double-loop Celtic interlace.
   
   Abbreviations for cable:
   - C4F: sl2 to CN, hold front, k2, k2 from CN
   - C4B: sl2 to CN, hold back, k2, k2 from CN
   - T4F: sl2 to CN hold front, p2, k2 from CN  
   - T4B: sl2 to CN hold back, k2, p2 from CN
   - T3F: sl1 to CN hold front, p2, k1 from CN
   - T3B: sl2 to CN hold back, k1, p2 from CN
   
   Let me use a standard Celtic cable design from my knowledge:

   **Panel A - Celtic Cable (18 stitches, 24-row repeat)**:
   
   Setup: p2, k2, p2, k4, p2, k2, p2
   
   This is getting complex. Let me design a clean, workable Celtic cable that I can chart properly.

   **Revised Celtic Cable Panel (16 sts wide)**:
   
   Using the standard interlocking oval Celtic design:
   
   ```
   Row 1 (RS):  p4, C4B, C4F, p4          [or with different structure]
   ```
   
   Actually let me use the classic approach:
   
   **Celtic Plait Cable (12 sts)** - simpler but still distinctly Celtic:
   Row 1: *C4B, C4F* (work over 12 sts as: sl2 to CN back, k2, k2 from CN, sl2 to CN front, k2, k2 from CN, sl2 to CN back, k2, k2 from CN)
   
   Hmm, 12 sts: C4B (4), C4F (4), last 4 knit? That's not quite right.
   
   Let me go with:
   **Celtic Knot Panel (24 sts, 16-row repeat)** — This is more authentically Celtic and appropriate for advanced knitters:
   
   I'll design this carefully:
   
   Stitches: 4 traveling cable groups across 24 stitches
   
   Actually for a pattern document, let me design something that I can chart accurately:

   **My Celtic Cable Design for this pattern:**
   
   Panel width: 20 stitches
   Repeat: 24 rows
   
   Structure: Two interlocked diamonds with crossing cables
   
   Row 1 (RS): p4, T4B, p4, T4F, p4
   Actually this doesn't work over 20 sts cleanly... let me count:
   p4 (4), T4B (4), p4 (4), T4F (4), p4 (4) = 20 sts. Yes!
   
   But T4B moves the cable diagonally. This will create a traveling cable, not quite Celtic interlace.
   
   For a genuine Celtic interlace cable, I need the cables to overlap and interlock. Let me design:

   **CELTIC CABLE PANEL: 24 stitches wide, 32-row repeat**
   
   This will be an interlocking diamond pattern:
   
   Abbreviations:
   - C6B: sl3 to CN back, k3, k3 from CN
   - C6F: sl3 to CN front, k3, k3 from CN  
   - T5B: sl3 to CN back, k2, (p1, k2) from CN
   - T5F: sl2 to CN front, k1, p1, k2... 
   
   This is getting overly complex for a chart. Let me use a clean, recognizable Celtic cable that works:

   **FINAL CELTIC CABLE DESIGN:**

   I'll use a 16-stitch Celtic interlace panel with 16-row repeat — clear, recognizable, authentically Celtic:
   
   Cable Abbreviations needed:
   - C4B: sl2 to CN, hold back, k2, k2 from CN
   - C4F: sl2 to CN, hold front, k2, k2 from CN
   - T3B: sl1 to CN, hold back, k2, p1 from CN
   - T3F: sl2 to CN, hold front, p1, k2 from CN
   - T4B: sl2 to CN, hold back, k2, p2 from CN
   - T4F: sl2 to CN, hold front, p2, k2 from CN
   
   Panel (16 sts, 16-row repeat):
   Set up row: p2, k4, p4, k4, p2
   
   Row 1: p2, C4F, p4, C4B, p2 [16]
   Row 2 (and all WS rows): work sts as they present (k the p, p the k)
   Row 3: p2, k2, T4F, T4B, k2, p2
   — wait, T4F over 4 sts + T4B over 4 sts in middle... let me count: p2, k2 (4), T4F (4), T4B (4), k2, p2 = 2+2+4+4+2+2 = 16 ✓
   Row 5: p2, T4F... 
   
   Let me think about this more carefully with a full chart:
   
   Actually, I'll design the classic interlocking cable that creates the Celtic look:
   
   **Panel of 16 sts:**
   The idea: Two C4 cables traveling toward each other, crossing in the middle, then traveling back out, creating a diamond/interlocked loop shape.
   
   Let me use T3B and T3F (traveling over 3 stitches: 2 knit + 1 purl):
   
   Setup (not counted in repeat): p1, k2, p2, k2, p2, k2, p2, k2, p1 = 16 sts? 1+2+2+2+2+2+2+2+1=16 ✓
   
   Hmm, this is getting complicated. For a clean chart, let me use:
   
   **SIMPLEST AUTHENTIC CELTIC CABLE (12 sts + 2 border = 14 sts)**:
   
   Actually you know what, let me just design a solid 16-stitch Celtic cable and chart it cleanly:

   **Celtic Cable Panel A: 16 stitches, 16-row repeat**
   
   This creates an interlocking diamond Celtic motif.
   
   Key: All WS rows: k all k sts, p all p sts as they appear (work stitches as set)
   
   RS (odd) rows:
   Row 1: p2, k2, p2, k2, p2, k2, p2 — wait that's only 14. Let me be explicit:
   
   16 stitch panel layout:
   Positions: 1-2, 3-4, 5-6, 7-8, 9-10, 11-12, 13-14, 15-16
   
   Let me use a well-known structure:
   
   **Celtic Interlace Panel (16 sts):**
   
   The classic Celtic interlace is formed by two interlocking figure-8 cables.
   
   Row 1 (RS): p3, k2, p2, k2, p2, k2, p3 (= 16)
   Row 2 (WS): k3, p2, k2, p2, k2, p2, k3 (= 16)
   Row 3: p3, C4F, p2, C4B... wait: p3(3) + C4F(4) + p2(2) = 9, then C4B(4) + p3(3) = 16. Yes!
   But C4F starts on sts 4-7 (k2p2 or k4?). I need the cable sts to be knit sts.
   
   Let me redo with k positions as knit, p positions as purl:
   
   Row 1: p3, [k4], p2, [k4], p3 = 3+4+2+4+3 = 16 ✓
   Row 2: k3, [p4], k2, [p4], k3
   Row 3: p3, C4F (sl2 to CN front, k2, k2 from CN), p2, C4B (sl2 to CN back, k2, k2 from CN), p3
   Row 4: k3, p4, k2, p4, k3
   Row 5: p2, T3B (sl2 to CN back, k1, p2 from CN — NO, T3B usually = sl2 to CN back, k2, p1... 
   
   Okay I need to be precise. Let me use:
   - T3B: sl next 2 sts to CN, hold at back, k1 from LH needle, then p2 from CN — NO
   
   Standard definitions:
   - T3B (twist 3 back): sl1 to CN hold BACK, k2 from LH needle, p1 from CN [3 sts → 3 sts: results in k2, p1 arrangement moving right]
   - T3F (twist 3 front): sl2 to CN hold FRONT, p1 from LH needle, k2 from CN [3 sts → 3 sts: results in p1, k2 arrangement moving left]
   - T4B: sl2 to CN hold BACK, k2, p2 from CN [4 sts → 4 sts]  
   - T4F: sl2 to CN hold FRONT, p2, k2 from CN [4 sts → 4 sts]

   For the Celtic interlace effect with 16-stitch panel, the cables need to travel diagonally. Let me try a different, cleaner approach:

   I will design the Celtic cable using only C6B, C6F, and straight k/p arrangements. No traveling stitches — just a plait-style Celtic cable that is unmistakably Celtic:
   
   **Celtic Plait (18 sts, 12-row repeat)** — Classic and clean:
   
   Row 1 (RS): p3, k12, p3
   Row 2 (WS): k3, p12, k3
   Row 3: p3, C6B, C6F, p3 [= p3, (sl3 back, k3, k3 from CN), (sl3 front, k3, k3 from CN), p3]
   Row 4: k3, p12, k3
   Row 5: p3, k12, p3
   Row 6: k3, p12, k3
   Row 7: p3, k3, C6F, k3, p3 [= p3, k3, sl3 front k3 k3 from CN, k3, p3]
   Row 8: k3, p12, k3
   Row 9: p3, k12, p3
   Row 10: k3, p12, k3
   Row 11: p3, C6B, C6F, p3
   Row 12: k3, p12, k3

   Hmm, that repeats rows 3 and 11 which are the same. Let me try:
   
   Row 1: p3, k12, p3
   Row 2: k3, p12, k3
   Row 3: p3, C6B, C6F, p3
   Row 4: k3, p12, k3
   Row 5: p3, k12, p3
   Row 6: k3, p12, k3
   Row 7: p3, k3, C6B, k3, p3 — wait this is 3+3+6+3+3=18 but C6B spans across two sections...
   
   The classic Celtic plait uses:
   Row 3: C6B, C6F (over 12 sts between borders)
   Row 7: k3, C6B, k3 — but this doesn't work as written since C6B is a complete 6-st cable
   
   Actually the standard 3-strand braid cable (which reads as Celtic):
   Over 12 sts (3 groups of 4):
   Row 1: k12
   Row 2: p12
   Row 3: C4B, k4, C4F [= C4B (4) + k4 (4) + ... wait that's already 8+4=12 if C4B and k4 and C4F... C4B(4) + k4(4) = 8, not 12]
   
   Hmm. Let me try over 12 sts:
   Row 3: C4B (sts 1-4), C4F (sts 5-8), then sts 9-12 = k4? No...
   
   The 3-cable braid (Celtic plait effect) over 12 sts:
   Round 1: k12
   Round 2: C4B (sts 1-4), k4 (sts 5-8), C4F (sts 9-12)  — NO, C4F on sts 9-12 means sl2 front, k2, k2 from CN, that just recables 4 sts. This creates a braid.
   
   Wait, for a 3-strand braid:
   Round 1: k12
   Round 3: C4B, C4F, k4 — 4+4+4=12 ✓ but this creates braid starting from left
   Round 5: k4, C4B, C4F — 4+4+4=12 ✓ progresses the braid
   Round 7: C4B, C4F, k4 — repeats
   
   This creates a braid but not specifically Celtic knot.
   
   You know what, for this pattern I will design an actual Celtic knot cable that I know works. Let me use the "Celtic Interlace" which is a well-known 16-row, 20-stitch pattern that creates genuinely interlaced Celtic knotwork. I'll design it with T4B and T4F cables:
   
   **FINAL CELTIC CABLE DESIGN:**
   
   **Panel of 24 sts, 24-row repeat**
   Creates two interlocked oval Celtic rings (classic Celtic knotwork appearance)
   
   Abbreviations:
   - C4B: sl2 to CN, hold back, k2, k2 from CN
   - C4F: sl2 to CN, hold front, k2, k2 from CN
   - T4B: sl2 to CN, hold back, k2, p2 from CN
   - T4F: sl2 to CN, hold front, p2, k2 from CN
   - T3B: sl1 to CN, hold back, k2, p1 from CN
   - T3F: sl2 to CN, hold front, p1, k2 from CN
   
   Hmm, let me think about this differently. Let me just carefully lay out a 20-stitch Celtic cable:
   
   Setup row (WS): k4, p4, k4, p4, k4 = 20 sts
   
   Row 1 (RS): p4, C4B, p4, C4F, p4 = 4+4+4+4+4 = 20 ✓
   Row 2 (WS): k4, p4, k4, p4, k4 = 20
   Row 3: p2, T4B, T4F, T4B, T4F, p2
   = p2(2) + T4B(4) + T4F(4) + T4B(4) + T4F(4) + p2(2) = 20 ✓
   But after T4B: the 2 k sts move right over 2 p sts → position shifts
   This changes the layout to: p2, k2, [interleaved], k2, p2 area
   
   This is getting very complex to track. Let me just USE an established Celtic cable from knitting reference knowledge:
   
   Here is a verified Celtic Interlace Cable pattern (this is based on well-established Celtic cable construction):
   
   **CELTIC INTERLACE PANEL: 24 sts, 32-row repeat**
   
   I'll use a simpler but authentically Celtic design — the Celtic Braid with interlocking ovals:
   
   Using T3B/T3F traveling stitches and C4B/C4F:
   
   Stitch panel: 24 sts
   
   Row 1 (RS): p4, k4, p8, k4, p4
   Row 2 & all WS: work as set (k over k, p over p) 
   
   Hmm this is 4+4+8+4+4=24 ✓
   
   Actually let me just commit to a specific well-known Celtic cable design and write it out. I'll base it on the "Interlocked Diamond" Celtic pattern:

   **CELTIC KNOT CABLE — PANEL OF 16 STS, 24-ROW REPEAT**
   
   Key abbreviations for this cable:
   - C4B: sl2 to CN hold back, k2, k2 from CN
   - C4F: sl2 to CN hold front, k2, k2 from CN  
   - T4B: sl2 to CN hold back, k2, p2 from CN
   - T4F: sl2 to CN hold front, p2, k2 from CN
   
   The panel creates two interlocking ovals. Starting arrangement:
   k4, p4, k4, p4 — NO border stitches on this panel (borders are separate)
   
   Wait, I want a panel with a purl border so it stands out from the background. Let me use:
   p2 border | 12-stitch cable | p2 border = 16 sts total
   
   The 12-stitch cable center creates the Celtic motif.
   
   For a 12-stitch Celtic interlace (this is a Celtic plait = recognizable Celtic knotwork):
   
   Row 1 (RS): k12
   Row 2 (WS): p12
   Row 3: C6B, C6F [sl3 to CN back, k3, k3 from CN; sl3 to CN front, k3, k3 from CN] = 6+6=12 ✓
   Row 4: p12
   Row 5: k12
   Row 6: p12
   Row 7: k3, C6B, k3 [k3, sl3 to CN back, k3, k3 from CN, k3] = 3+6+3=12 ✓
   Row 8: p12
   Row 9: k12
   Row 10: p12
   Row 11: C6B, C6F (same as row 3)
   Row 12: p12
   
   This is a 12-row repeat of the Celtic plait. Actually, for the plait to work properly:
   Row 3: C6B, C6F — right cable crosses behind, left cable crosses in front → creates an 'X' with right strand going behind
   Row 7: k3, C6B, k3 — middle portion crosses
   
   Hmm, the standard Celtic plait (3-cable braid) goes:
   Row 1: k12
   Row 2: p12  
   Row 3: C4B, k4, C4F — sl2 back k2 k2 from CN, k4, sl2 front k2 k2 from CN = 4+4+4=12
   Row 4: p12
   Row 5: k12
   Row 6: p12
   Row 7: k2, C4F, C4B, k2 — k2, sl2 front k2 k2 from CN, sl2 back k2 k2 from CN, k2 = 2+4+4+2=12
   Row 8: p12
   Repeat rows 1-8
   
   This creates a clear braid/plait that reads as Celtic! Let me verify:
   Row 3: [C4B][k4][C4F] = strand 1 crosses behind strand 2 at left; strand 3 crosses in front of strand 2 at right. Creates braid.
   Row 7: k2[C4F][C4B]k2 = middle-left cross in front, middle-right cross behind. Continues braid.
   Yes! This is the classic Celtic plait. 8-row repeat, 12 stitches wide.
   
   Now with p2 borders: total panel = 2 + 12 + 2 = 16 sts ✓
   
   Full panel:
   Row 1 (RS): p2, k12, p2
   Row 2 (WS): k2, p12, k2
   Row 3: p2, C4B, k4, C4F, p2
   Row 4: k2, p12, k2
   Row 5: p2, k12, p2
   Row 6: k2, p12, k2
   Row 7: p2, k2, C4F, C4B, k2, p2
   Row 8: k2, p12, k2
   Repeat rows 1-8
   
   This is clean, workable, and genuinely looks like a Celtic braid/plait. ✓
   
   Now I need to think about whether to use a more complex interlocking Celtic design. For advanced knitters with "Celtic cable motif," the plait might be considered too simple. Let me add interlocking rings as a second chart:
   
   Actually, since the pattern says "Celtic cable motif" and this is advanced, I'll use the Celtic plait (Chart A) as the main motif, and add a Celtic diamond/interlace for the neck cuff (Chart B). Or I can use a more complex Celtic cable for all areas.
   
   Let me design a more impressive Celtic cable for the main body and sleeve panels:
   
   **MAIN CELTIC CABLE — Panel of 24 sts, 16-row repeat**
   Creates an interlocked infinity/trinity knot appearance
   
   Abbreviations:
   - C4B: sl2 CN back, k2, k2 from CN
   - C4F: sl2 CN front, k2, k2 from CN
   - T3B: sl1 to CN hold back, k2, p1 from CN
   - T3F: sl2 to CN hold front, p1, k2 from CN
   - T4B: sl2 to CN hold back, k2, p2 from CN  
   - T4F: sl2 to CN hold front, p2, k2 from CN
   
   Panel setup (24 sts): p2, k4, p4, k4, p4, k4, p2
   = 2+4+4+4+4+4+2 = 24 ✓
   
   Row 1 (RS): p2, C4F, p4, k4, p4, C4B, p2
   Row 2 (WS): k2, p4, k4, p4, k4, p4, k2
   Row 3: p2, k2, T4F, T4B, T4F, T4B, k2, p2
   — Let me count: p2(2) k2(2) T4F(4) T4B(4) T4F(4) T4B(4) k2(2) p2(2) = 24 ✓
   But the T moves will shift the k/p arrangement...
   
   This is getting very complex and hard to verify in my head. Let me take a step back and use a completely clean approach.
   
   **FINAL DECISION ON CABLE DESIGN:**
   
   I will use TWO cable charts:
   
   **Chart A: Celtic Plait Cable (16 sts, 8-row repeat)**
   — Used on body side panels and sleeve centre panels
   — The classic 3-strand braid with purl borders = unmistakably Celtic plait
   
   **Chart B: Celtic Diamond Cable (20 sts, 24-row repeat)**  
   — Used on centre front/back body panels
   — More complex interlocking diamond
   
   For Chart B, I'll use a clean construction:
   
   Panel: 20 sts
   T4B: sl2 to CN hold back, k2, p2 from CN
   T4F: sl2 to CN hold front, p2, k2 from CN
   C4B: sl2 to CN hold back, k2, k2 from CN
   C4F: sl2 to CN hold front, k2, k2 from CN
   
   Starting arrangement: p2, k4, p8, k4, p2 = 20 sts
   
   Row 1 (RS): p2, C4F, p8, C4B, p2
   [p2, C4F, p8, C4B, p2] = 2+4+8+4+2 = 20 ✓
   
   Row 2 (WS): k2, p4, k8, p4, k2
   
   Row 3: p2, T4F, p4, C4B, C4F, p4, T4B, p2... wait
   p2(2) + T4F(4) = 6, + p4(4) = 10, + C4B(4) + C4F(4) = 18, + p4... that's only: 2+4+4+4+4 = 18 and I still need +... no
   
   Let me recalculate Row 3 over 20 sts:
   p2, T4F, p4, C4F, p4, T4B, p2
   = 2+4+4+4+4+4+2 = 24 — too many!
   
   p2, T4F, p8, T4B, p2? 
   = 2+4+8+4+2 = 20 ✓
   But T4F (sl2 front, p2, k2): sts 3-6 → after: p2, k2 arrangement, the k2 sts now sit more to the left
   And T4B (sl2 back, k2, p2): the k2 crosses over p2 to the right
   
   After Row 3: k2 groups have moved: one group moved 2 sts to the right (T4F) and one group moved 2 sts to the left (T4B)
   New arrangement: p4, k2, p4, k2, p4 — but that's 4+2+4+2+4=16, not 20...
   
   Hmm. Let me think again. 
   
   T4F = sl 2 sts to CN hold FRONT, p2 from LH needle, k2 from CN
   So: sts in = [k2, p2] → sts out = [p2, k2] but shifted: k2 group moves 2 sts to the left
   T4B = sl 2 sts to CN hold BACK, k2 from LH needle, p2 from CN  
   So: sts in = [p2, k2] → sts out = [k2, p2] but shifted: k2 group moves 2 sts to the right
   
   Starting: p2 [k4] p8 [k4] p2 (positions 1-20: pp-kkkk-pppppppp-kkkk-pp)
   
   Wait — I had C4B/C4F in row 1 treating k4 as two groups of k2, or as one k4?
   
   Let me be more explicit:
   Position 1-2: p2
   Position 3-6: k4 (cable group 1)
   Position 7-14: p8 (centre purl)
   Position 15-18: k4 (cable group 2)
   Position 19-20: p2
   
   Row 1: p2, C4F, p8, C4B, p2 — cables within each k4 group (just a cable twist, no travel) ✓ (20 sts)
   Row 2: k2, p4, k8, p4, k2
   
   Row 3 (travel outward? inward?): 
   I want the cables to travel toward the centre:
   Left cable group (pos 3-6) moves right by 2: needs T4F (moving left group right isn't standard — let me reconsider)
   
   T4F: [k2, p2] → [p2, k2]: the k2 moves to the right (travels right when viewed on RS)... Actually:
   T4F (sl2 to CN FRONT, p2, k2 from CN): 
   - You're working on 4 sts
   - sl first 2 sts (which are k2) to CN, hold FRONT
   - p next 2 sts from LH needle (the p2)
   - k2 from CN
   Result on RS: the k2 which was on the left now appears on the right = k2 moves RIGHT ??? 
   
   Wait no. If the k2 were in positions 3-4 and p2 in positions 5-6:
   T4F on positions 3-6: sl sts 3-4 (k2) to CN front, p sts 5-6, k sts 3-4 from CN
   Result: positions 3-4 now = p2 (formerly pos 5-6), positions 5-6 = k2 (formerly pos 3-4)
   So the k2 group MOVED RIGHT by 2 positions. T4F = cable group moves RIGHT. ✓
   
   T4B (sl2 to CN BACK, k2, p2 from CN):
   If p2 in pos 3-4 and k2 in pos 5-6:
   sl sts 3-4 (p2) to CN back, k sts 5-6, p sts 3-4 from CN
   Result: pos 3-4 = k2 (formerly pos 5-6), pos 5-6 = p2 (formerly pos 3-4)
   So the k2 group MOVED LEFT by 2 positions. T4B = cable group moves LEFT. ✓
   
   Now back to Row 3, I want to create a Celtic diamond where the two k4 groups split and travel toward each other (converge at centre):
   
   Left group (pos 3-6, k4): needs to travel RIGHT → split into k2, k2 and travel each differently
   Right group (pos 15-18, k4): needs to travel LEFT
   
   For converging toward centre:
   Left k4 group (pos 3-6): 
   - left half (pos 3-4, k2) stays
   - right half (pos 5-6, k2): travels right using T4F on pos 5-8 [k2 at 5-6, p2 at 7-8]
   
   Right k4 group (pos 15-18):
   - right half (pos 17-18, k2) stays
   - left half (pos 15-16, k2): travels left using T4B on pos 13-16 [p2 at 13-14, k2 at 15-16]
   
   Row 3:
   pos 1-2: p2 (unchanged)
   pos 3-4: k2 (left half of left group, unchanged)
   pos 5-8: T4F [k2,p2 → p2,k2] — the k2 moves to pos 7-8
   pos 9-12: p4 (unchanged from the p8 section)
   pos 13-16: T4B [p2,k2 → k2,p2] — the k2 moves to pos 13-14
   pos 17-18: k2 (right half of right group, unchanged)
   pos 19-20: p2 (unchanged)
   
   After Row 3:
   pos 1-2: p2
   pos 3-4: k2
   pos 5-6: p2
   pos 7-8: k2 (moved right)
   pos 9-12: p4
   pos 13-14: k2 (moved left)
   pos 15-16: p2
   pos 17-18: k2
   pos 19-20: p2
   
   Row 4 (WS): work as set
   k2, p2, k2, p2, k4, p2, k2, p2, k2 — wait:
   pos 1-2: k2 (WS of p2)
   pos 3-4: p2 (WS of k2)
   pos 5-6: k2 (WS of p2)
   pos 7-8: p2 (WS of k2)
   pos 9-12: k4 (WS of p4)
   pos 13-14: p2 (WS of k2)
   pos 15-16: k2 (WS of p2)
   pos 17-18: p2 (WS of k2)
   pos 19-20: k2 (WS of p2)
   Row 4: k2, p2, k2, p2, k4, p2, k2, p2, k2 = 2+2+2+2+4+2+2+2+2 = 20 ✓
   
   Row 5: Continue traveling toward centre:
   Left-side k2 (pos 3-4) travels right: T4F on pos 3-6 [k2 at 3-4, p2 at 5-6] → p2 at 3-4, k2 at 5-6
   Moving k2 (pos 7-8) continues right: T4F on pos 7-10 [k2 at 7-8, p2 at 9-10] → p2 at 7-8, k2 at 9-10
   
   Right side:
   Moving k2 (pos 13-14) continues left: T4B on pos 11-14 [p2 at 11-12, k2 at 13-14] → k2 at 11-12, p2 at 13-14
   Right k2 (pos 17-18) travels left: T4B on pos 15-18 [p2 at 15-16, k2 at 17-18] → k2 at 15-16, p2 at 17-18
   
   Row 5:
   pos 1-2: p2
   pos 3-6: T4F → p2, k2 (k2 was at 3-4, moves to 5-6)
   pos 7-10: T4F → p2, k2 (k2 was at 7-8, moves to 9-10)
   pos 11-14: T4B → k2, p2 (k2 moves from 13-14 to 11-12)
   pos 15-18: T4B → k2, p2 (k2 moves from 17-18 to 15-16)
   pos 19-20: p2
   
   After Row 5:
   pos 1-2: p2
   pos 3-4: p2 (from T4F of 3-6)
   pos 5-6: k2 (from T4F of 3-6)
   pos 7-8: p2 (from T4F of 7-10)
   pos 9-10: k2 (from T4F of 7-10)
   pos 11-12: k2 (from T4B of 11-14)
   pos 13-14: p2 (from T4B of 11-14)
   pos 15-16: k2 (from T4B of 15-18)
   pos 17-18: p2 (from T4B of 15-18)
   pos 19-20: p2
   
   Positions 9-10 and 11-12 both have k2! They are meeting at the centre!
   
   Row 6 (WS): as set
   p2, p2, k2, p2, k2, p2, k2, p2, k2, p2, p2? Wait:
   
   Let me redo: WS mirror of RS:
   pos 1-2: k2 (WS of p2)
   pos 3-4: k2 (WS of p2)
   pos 5-6: p2 (WS of k2)
   pos 7-8: k2 (WS of p2)
   pos 9-10: p2 (WS of k2)
   pos 11-12: p2 (WS of k2)
   pos 13-14: k2 (WS of p2)
   pos 15-16: p2 (WS of k2)
   pos 17-18: k2 (WS of p2)
   pos 19-20: k2 (WS of p2)
   Row 6: k4, p2, k2, p4, k2, p2, k4 = 4+2+2+4+2+2+4=20 ✓
   
   Row 7: The four k2 groups are at: 5-6, 9-10, 11-12, 15-16. This is the "centre" moment. Now do a cable cross at the centre AND continue pattern:
   
   Centre cross: Cable the two meeting k2 groups:
   C4F or C4B on pos 9-12: [k2 at 9-10, k2 at 11-12] → C4B: sl2 back, k2, k2 from CN
   
   Outer left k2 (pos 5-6): start traveling back out (left):
   T4B on pos 3-6 [p2 at 3-4, k2 at 5-6] → k2 at 3-4, p2 at 5-6
   
   Outer right k2 (pos 15-16): start traveling back out (right):
   T4F on pos 15-18 [k2 at 15-16, p2 at 17-18] → p2 at 15-16, k2 at 17-18
   
   Row 7:
   pos 1-2: p2
   pos 3-6: T4B → k2, p2 (k2 moves left to pos 3-4)
   pos 7-8: p2 (unchanged)
   pos 9-12: C4B → k4 crossed
   pos 13-14: p2 (unchanged)
   pos 15-18: T4F → p2, k2 (k2 moves right to pos 17-18)
   pos 19-20: p2
   
   After Row 7:
   pos 1-2: p2
   pos 3-4: k2
   pos 5-6: p2
   pos 7-8: p2
   pos 9-12: k4 (cabled)
   pos 13-14: p2
   pos 15-16: p2
   pos 17-18: k2
   pos 19-20: p2
   
   Hmm, pos 7-8 and 13-14 and 15-16 have purl which is fine. But I seem to have lost some k2 groups. After row 7 I only have k2 at pos 3-4, k4 at pos 9-12, k2 at pos 17-18. That seems right for a diamond — the cables are at the outer points and crossing in the centre.
   
   This is getting very intricate. I'm going to simplify significantly for the actual pattern output. I'll use the Celtic plait (which is genuinely Celtic-looking) as Chart A, and present a slightly more complex interlocked Celtic diamond as Chart B. I'll describe them clearly.

   For the pattern, I'll use:
   
   **CHART A: Celtic Plait (16 sts, 8-row repeat)**
   Used on sleeve centre and body side panels
   
   Row 1 (RS): p2, k12, p2
   Row 2 (WS): k2, p12, k2
   Row 3: p2, C4B, k4, C4F, p2
   Row 4: k2, p12, k2
   Row 5: p2, k12, p2
   Row 6: k2, p12, k2
   Row 7: p2, k4, C4B, k4, p2 — wait, k4+C4B+k4 = 4+4+4=12 ✓ but I want C4F for the second variant
   
   Actually for the braid, rows 3 and 7 should create opposing crossings:
   Row 3: C4B, k4, C4F (right strand goes behind left; left strand goes in front of right at the outer edges)
   Row 7: k4, C4B, k4 OR k2, C4F, C4B, k2
   
   Let me use the verified Celtic braid formula (I'll use C4B for both to create a consistent twist):
   
   For a proper braided look:
   Row 3: C4B, k4, C4F — first and last groups cross
   Row 7: k2, C4F, C4B, k2 — middle crosses happen staggered
   
   Let me verify row 7: k2, C4F, C4B, k2 = 2+4+4+2=12 centre sts ✓
   
   Full Chart A:
   Row 1: p2, k12, p2
   Row 2: k2, p12, k2
   Row 3: p2, [C4B, k4, C4F], p2
   Row 4: k2, p12, k2
   Row 5: p2, k12, p2
   Row 6: k2, p12, k2
   Row 7: p2, [k2, C4F, C4B, k2], p2
   Row 8: k2, p12, k2
   Repeat rows 1-8.
   
   Verification of row 3 cable stitches (12 sts):
   C4B: sl2 to CN back, k2, k2 from CN → uses sts 1-4 of the 12 [original arrangement: k,k,k,k] → cables last 2 behind first 2
   Then k4 straight → sts 5-8
   Then C4F: sl2 to CN front, k2, k2 from CN → uses sts 9-12 → cables first 2 in front of last 2
   Total: 4+4+4=12 ✓
   
   Verification of row 7:
   k2 → sts 1-2
   C4F: sl2 front, k2, k2 from CN → sts 3-6
   C4B: sl2 back, k2, k2 from CN → sts 7-10
   k2 → sts 11-12
   Total: 2+4+4+2=12 ✓
   
   CHART A VERIFIED ✓
   
   Now for **Chart B: Celtic Knot Diamond (20 sts, 16-row repeat)**
   
   I'll use the interlocking diamond that I was working out above, simplified:
   
   This creates two diamonds that interlock, giving the classic Celtic knotwork appearance.
   
   Starting arrangement: p4, k4, p4, k4, p4 = 4+4+4+4+4=20 ✓
   
   C4B, C4F as before.
   T4F: sl2 CN front, p2, k2 from CN (k2 travels RIGHT)
   T4B: sl2 CN back, k2, p2 from CN (k2 travels LEFT)
   
   Row 1 (RS): p4, C4F, p4, C4B, p4
   Row 2 (WS): k4, p4, k4, p4, k4
   Row 3: p2, T4B, T4F, T4B, T4F, p2
   
   Row 3 breakdown: p2(2) + T4B(4) + T4F(4) + T4B(4) + T4F(4) + p2(2) = 20 ✓
   
   But where exactly do these start? Let me number positions 1-20:
   1-2: p2 (start of row)
   3-6: T4B on positions 3-6: positions 3-4 had p (from p4 at 1-4, so pos 3-4 are the 3rd-4th of that p4), positions 5-6 are the 1st-2nd of the k4 at 5-8.
   
   Wait, I need to re-setup the starting arrangement. Let me be precise:
   
   Starting RS arrangement:
   Pos 1-4: p4
   Pos 5-8: k4
   Pos 9-12: p4
   Pos 13-16: k4
   Pos 17-20: p4
   
   Row 3: I want both k4 groups to split and travel inward (toward pos 10-11, the centre):
   
   Left k4 (pos 5-8):
   - Left pair (pos 5-6, k2) travels left: T4B on pos 3-6 [p2 at 3-4, k2 at 5-6] → k2 moves to pos 3-4
   - Right pair (pos 7-8, k2) travels right: T4F on pos 7-10 [k2 at 7-8, p2 at 9-10] → k2 moves to pos 9-10
   
   Right k4 (pos 13-16):
   - Left pair (pos 13-14, k2) travels left: T4B on pos 11-14 [p2 at 11-12, k2 at 13-14] → k2 moves to pos 11-12
   - Right pair (pos 15-16, k2) travels right: T4F on pos 15-18 [k2 at 15-16, p2 at 17-18] → k2 moves to pos 17-18
   
   Row 3 written:
   p2, T4B (pos 3-6), T4F (pos 7-10), T4B (pos 11-14), T4F (pos 15-18), p2
   = p2(2) + T4B(4) + T4F(4) + T4B(4) + T4F(4) + p2(2) = 20 ✓
   
   After Row 3:
   Pos 1-2: p2 (unchanged from start)
   Pos 3-4: k2 (left pair, moved left)
   Pos 5-6: p2 (from T4B, 3-6)
   Pos 7-8: p2 (from T4F, 7-10, these were original p positions 7-8 of the p4 at 9-12, wait no)
   
   Hmm wait. Let me redo. T4F on pos 7-10: pos 7-8 had k2 (from k4 group), pos 9-10 had p2 (from p4 group). T4F = sl2 (pos 7-8, k2) to CN front, p2 from pos 9-10, k2 from CN. Result: pos 7-8 = p2, pos 9-10 = k2.
   
   T4B on pos 11-14: pos 11-12 had p2 (from p4 group), pos 13-14 had k2 (from k4 group). T4B = sl2 (pos 11-12, p2) to CN back, k2 from pos 13-14, p2 from CN. Result: pos 11-12 = k2, pos 13-14 = p2.
   
   After Row 3:
   Pos 1-2: p2
   Pos 3-4: k2 (was p, now k)  [T4B result]
   Pos 5-6: p2 (was k, now p)  [T4B result]
   Pos 7-8: p2 (was k, now p)  [T4F result]  
   Pos 9-10: k2 (was p, now k) [T4F result]
   Pos 11-12: k2 (was p, now k) [T4B result]
   Pos 13-14: p2 (was k, now p) [T4B result]
   Pos 15-16: p2 (was k, now p) [T4F result] — wait T4F on 15-18: pos 15-16 = k2, pos 17-18 = p2. T4F: sl2 (15-16, k2) front, p2 (from 17-18), k2 from CN. Result: pos 15-16 = p2, pos 17-18 = k2. Wait that's the k2 group moving to the RIGHT (from 15-16 to 17-18), which is OUTWARD.

   Hmm, I messed up the direction. T4F moves the k2 to the RIGHT. So for the RIGHT k4 group, the right pair (pos 15-16) moving RIGHT with T4F is moving OUTWARD (away from centre). And T4B moves k2 to the LEFT, so for the right k4 group, left pair (pos 13-14) moving LEFT with T4B is moving INWARD (toward centre). That's correct.
   
   For the LEFT k4 group:
   - Left pair (pos 5-6) moving LEFT (outward) uses T4B
   - Right pair (pos 7-8) moving RIGHT (inward) uses T4F
   
   So left group is splitting: outer pair goes outward, inner pair goes inward. And right group the same.
   This creates a DIAMOND shape for each cable group.
   
   After Row 3:
   Pos 1-2: p2
   Pos 3-4: k2 (outer-left of diamond 1, moved outward-left)
   Pos 5-6: p2
   Pos 7-8: p2
   Pos 9-10: k2 (inner-right of diamond 1, moved inward-right)
   Pos 11-12: k2 (inner-left of diamond 2, moved inward-left)
   Pos 13-14: p2
   Pos 15-16: p2
   Pos 17-18: k2 (outer-right of diamond 2, moved outward-right)
   Pos 19-20: p2
   
   Row 4 (WS): k2, p2, k4, p2, p2, k4, p2, k2 = ?
   WS: k where there's p on RS, p where there's k on RS:
   pos 1-2: k2, pos 3-4: p2, pos 5-8: k4, pos 9-10: p2, pos 11-12: p2, pos 13-16: k4, pos 17-18: p2, pos 19-20: k2
   Row 4: k2, p2, k4, p2, p2, k4, p2, k2 = 2+2+4+2+2+4+2+2=20 ✓
   
   Now Row 5: continue moving — inner pairs continue toward centre, outer pairs continue outward:
   
   Outer-left k2 (pos 3-4) continues left: T4B on pos 1-4: [p2 at 1-2, k2 at 3-4] → k2 at 1-2, p2 at 3-4
   Inner-right k2 (pos 9-10) continues right: T4F on pos 9-12: [k2 at 9-10, p2 at 11-12... wait pos 11-12 is k2! Not p2]
   
   Hmm! After row 3, pos 9-10 = k2 AND pos 11-12 = k2. They are adjacent! This means on Row 5 they should cable cross (that's the centre of the interlace):
   
   Centre crossing Row 5: C4B or C4F on pos 9-12: both are k2 groups meeting at the centre → C4B sl2 back, k2, k2 from CN = the inner-right (9-10) crosses behind inner-left (11-12), creating an "X" at the centre.
   
   Continue outer movements:
   Outer-left k2 (pos 3-4): T4B on pos 1-4 → k2 at 1-2
   Outer-right k2 (pos 17-18): T4F on pos 17-20 → k2 at 19-20
   
   Row 5:
   T4B on pos 1-4: [p2 at 1-2, k2 at 3-4] → k2, p2
   p4 (pos 5-8, unchanged)
   C4B on pos 9-12: [k2, k2] cross
   p4 (pos 13-16, unchanged)
   T4F on pos 17-20: [k2 at 17-18, p2 at 19-20] → p2, k2
   
   Row 5: T4B, p4, C4B, p4, T4F = 4+4+4+4+4=20 ✓
   
   After Row 5:
   Pos 1-2: k2 (from T4B)
   Pos 3-4: p2 (from T4B)
   Pos 5-8: p4
   Pos 9-10: k2 (crossed, from C4B - these are now the "strand going behind")
   Pos 11-12: k2 (crossed, from C4B - these are the "strand going in front")
   Pos 13-16: p4
   Pos 17-18: p2 (from T4F)
   Pos 19-20: k2 (from T4F)
   
   Pos 9-12: still k4 (after cable cross), and outer k2 are at pos 1-2 and 19-20.
   
   Now Row 7: the k4 at pos 9-12 starts traveling back out (splitting into two pairs again):
   - Left pair (pos 9-10) goes LEFT: T4B on pos 7-10: [p2 at 7-8, k2 at 9-10] → k2, p2
   - Right pair (pos 11-12) goes RIGHT: T4F on pos 11-14: [k2 at 11-12, p2 at 13-14] → p2, k2
   
   Outer pairs start coming back:
   - Left outer (pos 1-2, k2) starts moving RIGHT: T4F on pos 1-4: [k2 at 1-2, p2 at 3-4] → p2, k2 (k2 at pos 3-4)
   - Right outer (pos 19-20, k2) starts moving LEFT: T4B on pos 17-20: [p2 at 17-18, k2 at 19-20] → k2, p2 (k2 at pos 17-18)
   
   Row 7:
   T4F (pos 1-4) + p4 (pos 5-8... wait, pos 5-8 is p4 and pos 7-8 is part of it)
   
   Wait, T4B on pos 7-10 and T4F on pos 1-4 overlap at pos... they don't overlap:
   T4F: pos 1-4
   T4B: pos 7-10
   T4F: pos 11-14
   T4B: pos 17-20
   Plus anything in between: pos 5-6 (p2), pos 15-16 (p2)
   
   Row 7: T4F (1-4), p2 (5-6), T4B (7-10), T4F (11-14), p2 (15-16), T4B (17-20)
   = 4 + 2 + 4 + 4 + 2 + 4 = 20 ✓
   
   After Row 7: